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Correct description of shuffled_by_action #6

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Merged
sweeneyde merged 1 commit into from
Feb 27, 2026
Merged

Correct description of shuffled_by_action #6

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6 changes: 3 additions & 3 deletions README.md
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Original file line number Diff line number Diff line change
Expand Up @@ -382,8 +382,8 @@ More generally, we can shuffle the entries of the `Vector`
Using some function from `range(len(v))` to `range(result_size)`,
represented as a "action" `Vector`.
If `result_size` is not provided, it defaults to `len(v)`.
If the has duplicate entries `a[j1] == a[j2] == ...`,
then `v.shuffled_by_action(a)[a[j1]]` will be their sum `a[j1] + a[j2] + ...`,
If the action `a` has duplicate entries `a[j1] == a[j2] == ...`,
then `v.shuffled_by_action(a)[a[j1]]` will be their sum `v[j1] + v[j2] + ...`,
so each action `Vector` specifies a linear operation.

```pycon
Expand Down Expand Up @@ -448,4 +448,4 @@ Lattice(3, [[3, 0, 0], [0, 4, 4]], maxrank=2)
The single optional argument of `L.decompose(keep_together)` should be an iterable
of "component" iterables, and the integers in each component iterable are then ensured
to be placed in the same component. The summands are allocated "tightly",
with `maxrank` equal to their actual rank.
with `maxrank` equal to their actual rank.