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#635 asks whether M(p) is a difference of two topological-sector amplitudes. Whatever
decomposition anyone proposes, it has to be checked against the same thing: how the exact
configuration count splits by wrapping type, resolved by rank.
That table does not exist yet. #628 built a Fraction-exact per-rank-pair decomposition (P11, P20, P02), and #606 has the enumerator; neither resolves the topological type of
the wrapping, which is what a sector label is.
This ticket builds the table. It requires no theory and can be wrong in only one way —
failing to reproduce the committed M(p) when summed.
What to compute
For L = 3, 4, 5 (axis and diamond), enumerate configurations and, for each rank k
(number of occupied sites), tabulate exact integer counts cross-classified by:
primal (black, NN adjacency): wraps horizontally? vertically? both? neither?
matching (white, NN+NNN adjacency): same four
i.e. a 4 x 4 integer table per rank, per geometry, per L.
The tripwire
sum over the table, with D(C) = 1{black NN wraps} - 1{white NN+NNN wraps},
must reproduce the committed bernstein_counts EXACTLY, as integers.
At L = 3 axis that is [-1, -9, -36, -78, -90, -36, 36, 36, 9, 1]. If the collapsed table
does not return those integers bit-for-bit, the wrapping classifier is wrong and nothing else
in the report is usable. Run that check first, not last.
Why the finer resolution is worth the enumeration
Three things become visible only at this resolution, and all three matter to #635:
Where the cancellation in a_k comes from. The L = 3 coefficients change sign
between k = 5 and k = 6. Whether that is one term crossing zero or two large terms
nearly cancelling is a structural fact about the observable that we have never looked at,
and it bears directly on why the signal is hard to measure.
Deliverable
1. the 4x4-by-rank integer tables, committed as exact integers;
2. the tripwire passing at every L and geometry;
3. a short statement of what items 1-3 above turned out to be;
4. no interpretation beyond that -- the decomposition question is #635's.
Start now. Independent of #635's algebra.
#635 asks whether
M(p)is a difference of two topological-sector amplitudes. Whateverdecomposition anyone proposes, it has to be checked against the same thing: how the exact
configuration count splits by wrapping type, resolved by rank.
That table does not exist yet. #628 built a Fraction-exact per-rank-pair decomposition
(P11, P20, P02), and #606 has the enumerator; neither resolves the topological type ofthe wrapping, which is what a sector label is.
This ticket builds the table. It requires no theory and can be wrong in only one way —
failing to reproduce the committed
M(p)when summed.What to compute
For
L = 3, 4, 5(axis and diamond), enumerate configurations and, for each rankk(number of occupied sites), tabulate exact integer counts cross-classified by:
i.e. a
4 x 4integer table per rank, per geometry, perL.The tripwire
At
L = 3axis that is[-1, -9, -36, -78, -90, -36, 36, 36, 9, 1]. If the collapsed tabledoes not return those integers bit-for-bit, the wrapping classifier is wrong and nothing else
in the report is usable. Run that check first, not last.
Why the finer resolution is worth the enumeration
Three things become visible only at this resolution, and all three matter to #635:
D(C)uses a single wrapping predicateper lattice. If the horizontal and vertical wrapping counts differ, or if "both" carries
weight, then the two-sector picture may need more than two sectors and [P1 long-horizon] Is M(p) the difference of two topological sector amplitudes? Prove or kill the map before anyone builds a transfer matrix #635's candidate
decomposition is under-specified before it starts.
famously not simply complementary. The joint table says exactly how far from
complementary, per rank.
M(p) + M(1-p) != 0(#622 probe: invariant shape of the threshold law — S defined, W1–W5 adjudicated, g separated #628) is a consequence; this is thegenerating fact behind it.
a_kcomes from. TheL = 3coefficients change signbetween
k = 5andk = 6. Whether that is one term crossing zero or two large termsnearly cancelling is a structural fact about the observable that we have never looked at,
and it bears directly on why the signal is hard to measure.
Deliverable
Claim boundary
settle [P1 long-horizon] Is M(p) the difference of two topological sector amplitudes? Prove or kill the map before anyone builds a transfer matrix #635.
L = 5is2^25; if that is slow here,L = 3, 4are still worth having on their own andL = 5can follow [DeepSeek / heavy compute] Push the exact Bernstein ladder to L=5 by brute force — the last independently checkable rung #639's accelerated enumerator.Related: #635, #639, #628, #606, #321.