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Record the constant 3 on the longer reservoir layout (no new κ) - #4921
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Mister-Meeseeks merged 1 commit intoOct 23, 2026
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At r=2, p=2 and G=256 the sharp ratio is 2 + 2^{-15871} - 2^{-16126}.
It lies strictly between 2 and 3, so 3 replaces 1/6400 on this one
layout. No new kappa.
Co-authored-by: Cursor <cursoragent@cursor.com>
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Change and mathematical scope
Scoped comparison. No new κ. The selected conditional exponent stays
60403/20000000, and PR #4100 is not accepted.PR #4646 reaches
r (2/B + β) ≤ p 2^{-G} / 6400whenL ≤ p. On the admitted layoutp = 2,ell = 2,L = 65536,G = 256, andr = r_max = 2, the exact sharp ratio isThis is the
Cinr (2/B + β) = C p 2^{-G}. It lies strictly between 2 and 3, soC = 2fails andC = 3holds. The integer 3 replaces1/6400for this one inequality.The published window term has exact ratio
2 + 2^{-15869}and the same integer threshold. The production planr_max = 5,p = 9240576still satisfies5 · 3 · 6400 ≤ p, so1/6400is not retuned there.Task and overlap
624de9dc66858af0945e5f8a0942488d62280d43, fetched 2026-10-22T23:47:42Z, priority revision 7.formal-interface-lemma, scope refined. This is the open question of PR Record one #4174 production plan with L = p/6 (no new κ) #4913.1/6400line. PR Audit #4100 CRT.md's sparse exception repair tariff at Θ(p)-bit records: O(V) dense, o(V) sparse at every p (no new κ) #4328 supplies theL ≤ phypothesis.research/crt-reservoir-length-constant/.1/6400proof. No other evaluation of this ratio.Validation
Python 3.12, standard library only:
Observed
PASS_CRT_RESERVOIR_LENGTH_CONSTANT layout_p=2 layout_L=65536 r=2 G=256 sharp_between=2,3 integer_C=3, thenPASS_REGISTERED_RESEARCH_PACKAGE research/crt-reservoir-length-constant outcome=completed.Not run: the 104,864-plan census, the repair tariff, the
Eproduct, Lean, and Docker.Credit
Hiroki KUMAZAKI, PR #4174, for the constructor. PR #4646 for the
1/6400line. PR #4328 for theL ≤ phypothesis. Cinna Davis, PR #4100, for the CRT parameters.Prepared by James Reed with substantial Cursor Grok 4.7 assistance. Apache-2.0. No independent human review and no formal-kernel acceptance are claimed.
Open next questions
C = 3 r_max / psufficient atr = r_max? First step: show that every accepted layout hasG ≥ 256, so2 + 2^{1-62G} < 3.