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🧷 문제 링크
https://www.acmicpc.net/problem/15989
🧭 풀이 시간
35분
👀 체감 난이도
✏️ 문제 설명
1, 2, 3을 중복 사용해서 n을 만드는 방법의 수를 구하는 문제. 단, 같은 수를 두 번 연속 사용하면 안 됨.
🔍 풀이 방법
DP로 품
dp[j][1] = dp[j-1][1] (마지막이 1)
dp[j][2] = dp[j-2][1] + dp[j-2][2] (마지막이 2)
dp[j][3] = dp[j-3][1] + dp[j-3][2] + dp[j-3][3] (마지막이 3)
⏳ 회고
단순한 1차원 DP로 접근하려다 안 됨.
중복 해결하려면 2차원 필요