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🧷 문제 링크
https://www.acmicpc.net/problem/2655
🧭 풀이 시간
100분
👀 체감 난이도
✏️ 문제 설명
벽돌마다 밑면, 무게, 높이가 주어지는데, 벽돌을 쌓을 때 제일 높게 쌓는 경우의 벽돌 사용 개수와 각 인덱스를 순서대로 출력하라.
🔍 풀이 방법
일단 밑면의 넓이를 기준으로 내림차순으로 정렬했다.
그렇게 순차적으로 탐색해야 밑면은 무시할 수 있기 때문이다.
dp[i]= i번째 벽돌을 가장 위에 쌓았을 때의 최대 높이 로 상태정의하고i번째보다 작은 벽돌들을 순차적으로 탐색하면서 무게 조건을 확인해 dp[i]보다 큰 것이 있으면 그것으로 갱신한다.
⏳ 회고
LIS 어려워~. 비슷한 문제를 계속 풀어봐야겠어.