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🧷 문제 링크
https://www.acmicpc.net/problem/2482
🧭 풀이 시간
60분
👀 체감 난이도
✏️ 문제 설명
바로 옆에 있는 색은 선택하지 못한다. K개의 색을 고르는 경우의 수는?
🔍 풀이 방법
원형 DP이기 때문에, 첫번째를 선택하는 경우와 아닌 경우로 나눈다.
dp[i][j]: i번째 색에서 j개를 고른 경우의 수dp[i][j] = dp[i-1][j] + dp[i-2][j-1]⏳ 회고
dp는 꾸준히 풀어야 겠다. 안 풀다 푸니까 상태정의가 헷갈렸다.