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🧷 문제 링크
https://www.acmicpc.net/problem/9024
🧭 풀이 시간
30분
👀 체감 난이도
✏️ 문제 설명
두 수를 더했을 때, K와 가까운 값이 되는 경우의 수는?
🔍 풀이 방법
left = 0,right = N-1으로 놓고 두 index의 값을 합한다.K와 비교해 gap을 구하고, 기존 gap과 비교해서 작으면 새 gap을, 같으면 count++을 진행한다.
⏳ 회고
ez