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🧷 문제 링크
https://www.acmicpc.net/problem/2666
🧭 풀이 시간
40분
👀 체감 난이도
✏️ 문제 설명
n개의 벽장 중 2개만 열려있고, 순서대로 특정 벽장을 사용해야 할 때 문 이동 횟수의 최솟값을 구하는 문제
🔍 풀이 방법
dp[idx][a][b] = idx번째 벽장을 사용할 차례이고, 열린 문 위치가 a, b일 때 최소 이동 횟수
열린 문 2개의 위치를 상태로 관리
⏳ 회고
약간 어렵네요