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Write a 1^oo limit's exponent as a quotient - #2359
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The second remarkable limit writes a 1^oo power f^g as e^(g (f - 1)), and the product in its exponent the descent read as 0 * oo, NaN, the claim that there is no limit. Only a base of 1 plus a polynomial was answered, by another route: (cos(x))^(1/x^2) at 0, which is e^(-1/2), was NaN, and from the right unevaluated. 2.6.0 answers the same. The exponent is (f - 1) / (1/g) now, a 0/0 that a function of an indeterminate quotient asks whole since #2358. Asking a product whole in the descent instead answered these too, and also answered x * ln(x) at 0 two-sided with 0, which the two-sided reading keeps NaN, its left side not being real; the quotient keeps that convention. limitcheck on SEED=14 and 16, and at DEPTH=3 on 19 and 23, is master's exactly; 4194 limit, integration and remarkable-limit tests pass. Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
Codecov Report✅ All modified and coverable lines are covered by tests. Additional details and impacted files@@ Coverage Diff @@
## master #2359 +/- ##
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+ Coverage 86.76% 86.77% +0.01%
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Files 312 312
Lines 68807 68809 +2
Branches 20045 20045
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+ Hits 59697 59712 +15
+ Misses 4924 4911 -13
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Rafael-SOWNet
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A follow-up to #2358. No issue was filed.
cos(x)^(1/x^2)NaNe ^ (-1/2)limitright(cos(x)^(1/x^2), x, 0)e ^ (-1/2)(sin(x)/x)^(1/x^2)NaNe ^ (-1/6)cos(2x)^(1/x^2)NaNe ^ (-2)(1 + sin(x))^(1/x)NaNelimitright(cos(x)^(1/x), x, 0)1(1 + x)^(1/x),(1 - x^2)^(1/x^2)e,1/ex * ln(x),sin(x) * ln(x),x^xtwo-sidedNaNThe second remarkable limit writes a 1^oo power
f^gase^(g (f - 1)). The descent reads the product in its exponent as 0·∞, NaN, the claim that there is no limit. Only a base of 1 plus a polynomial reached an answer, by another route. The exponent is now the quotient(f - 1) / (1/g), a 0/0 that #2358 asks whole, and it has its value. Both places the rule builds the power are changed.Why a quotient and not a product. The first version gave a product in the descent the same whole-limit question as #2358's quotients. It answered all of these, and also answered
x * ln(x)at 0 two-sided with0,sin(x) * ln(x)too. Those are pinned NaN, because the two-sided reading keeps a limit whose left side is not real out of the reals (RealCodomainLimitTest,FirstRemarkableOverFactorsTest). The two-sided reading asks one-sided sub-limits, and those had relied on 0·∞ being NaN. Restricting the product retry to one-sided limits did not separate the two, so it was dropped. The quotient changes only the exponent the rule builds.limitcheck at
SEED=14and16, and atDEPTH=3on19and23, matches master exactly; none of those samples is a 1^∞ power. 4194 limit, integration and remarkable-limit tests pass.Tests:
AOneToTheInfinityLimitThroughItsExponentTest, 11 cases. 6 fail on master; the 2 controls and the 3 two-sided conventions pass on both. The full suite, AOT and the nine harnesses pass. There is a BREAKING-CHANGES entry, measured on 2.6.0.🤖 Generated with Claude Code