diff --git a/Probelm1.py b/Probelm1.py
new file mode 100644
index 00000000..88d484f9
--- /dev/null
+++ b/Probelm1.py
@@ -0,0 +1,41 @@
+#Product of Array Except Self
+
+#time complexity -> O2n -> On
+# Space complexity -> O1 since we are using only result array and not 2nd array
+
+class Solution:
+    def productExceptSelf(self, nums: List[int]) -> List[int]:
+        # generate an array from right to left saving the product till that position 
+        # For exampe for [1,2,3,4] will be [24, 12, 4, 1] in the result array
+        # then in the 2nd iteration from the start position keep the product in the single variable, and for each index the result product will be
+        # product of the variable and the value coming from the result array at that index, the update the index value in the same reult array
+        length = len(nums)
+        resultArr = [1]*length
+        product = 1
+        for i in range(length-1, -1, -1):
+            resultArr[i] = product
+            product *= nums[i]
+        product = 1
+        for i in range(0,length):
+            resultArr[i] = product * resultArr[i]
+            product = product *  nums[i]
+        return resultArr
+
+
+# 1,2,3,4
+
+# 24, 12, 4, 1
+PR = 1
+
+currentPos * PR = 24, 
+Pr = 1*1
+
+currentPos * PR = 12* 1
+pr = 1*2 = 2
+
+currentPos * PR = 4 * 2 = 8
+pr = currentPos * pr = 3 * 2 = 6
+
+currentPos * PR = 1 * 6 = 6
+
+# 24, 12, 8, 6
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diff --git a/Problem2.py b/Problem2.py
new file mode 100644
index 00000000..0ca0883c
--- /dev/null
+++ b/Problem2.py
@@ -0,0 +1,55 @@
+#Diagonal Traverse
+
+# TimeComplexity -> Omxn
+# Space complexity -> O1
+# Logic - > maintain the direction of the movement, when moving up, increase column by 1 and decrease row by 1, when moving down decrease column byy 1
+# and increase row by 1. While handling the edge cases at corners and borders
+
+# from typing import List
+
+
+class Solution:
+    def findDiagonalOrder(self, mat: List[List[int]]) -> List[int]:
+        row = 0
+        column = 0
+        rows = len(mat)
+        columns = len(mat[0])
+        result = []
+        resultLength = rows*columns
+        direction = 1 # 1 is for up and -1 is for down
+
+        #need to loop untill the result is of direct length
+        while len(result) < resultLength:
+            if direction == 1:
+                while (row >= 0 and column < columns ):
+                    result.append(mat[row][column])
+                    row-=1
+                    column+=1
+                direction = -1
+                if row == -1 and column == columns:
+                    row += 2
+                    column-=1
+                elif row == -1:
+                    row += 1
+                elif column == columns:
+                    row += 2
+                    column -= 1
+            
+            if direction == -1:
+                while (column >=0 and row < rows):
+                    result.append(mat[row][column])
+                    row+=1
+                    column-=1
+                direction = 1
+                if column == -1 and row == rows:
+                    column+=2
+                    row-=1
+                elif column == -1:
+                    column+=1
+                elif row == rows:
+                    column+=2
+                    row-=1
+        return result
+            
+sol = Solution()
+print(sol.findDiagonalOrder([[1,2,3],[4,5,6]]))
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diff --git a/Problem3.py b/Problem3.py
new file mode 100644
index 00000000..a23a3ea3
--- /dev/null
+++ b/Problem3.py
@@ -0,0 +1,60 @@
+#Spiral Matrix
+
+# Time complexity -> Omxn
+# Space complexity -> O1
+# Logic - > maintain the direction of the movement, when moving right, increase column by 1,moving down increse row by 1, moving left decrease column byy 1, 
+# moving up decrese row by 1. While handling the edge cases at borders and visited rows and columns
+
+from typing import List
+class Solution:
+    def spiralOrder(self, matrix: List[List[int]]) -> List[int]:
+        rows  = len(matrix)
+        columns = len(matrix[0])
+        # maintain endpoints in each direction indicating time to change directs
+        columnRight = columns - 1
+        columnleft = 0
+        rowTop = 0
+        rowBottom = rows - 1
+        
+        resultLength = rows*columns
+        result = []
+
+        if resultLength == 1:
+            return [matrix[0][0]]
+        
+        #need to loop untill the result is of direct length
+        while len(result) < resultLength:
+            print(result)
+            # move right
+            for col in range(columnleft,columnRight+1):
+                result.append(matrix[rowTop][col])
+            #rowTop needs to be incremented by 1
+            rowTop+=1
+            
+            if len(result) == resultLength:
+                return result
+            #Now move down
+            for row in range(rowTop,rowBottom+1):
+                result.append(matrix[row][columnRight])
+            #columnRight needs to be decreemnted by 1
+            columnRight-=1            
+
+            if len(result) == resultLength:
+                return result
+            #Now move left
+            for col in range(columnRight,columnleft-1, -1):
+                result.append(matrix[rowBottom][col])
+            #rowBottom needs to be decremented by 1
+            rowBottom-=1
+
+            if len(result) == resultLength:
+                return result
+            #Now move up
+            for row in range(rowBottom,rowTop-1,-1):
+                result.append(matrix[row][columnleft])
+            
+            #columnleft needs to be incremented by 1
+            columnleft+=1
+        return result
+sol = Solution()
+print(sol.spiralOrder([[1,2,3],[4,5,6],[7,8,9]]))
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