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Copy pathStackAsLinkedList.java
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102 lines (84 loc) · 2.35 KB
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// Time Complexity : O(1) for push, isEmpty, and peek and O(n) for pop
// Space Complexity : O(n)
// Did this code successfully run on Leetcode :yes - implement stack using queues
// Any problem you faced while coding this :
// Your code here along with comments explaining your approach
public class StackAsLinkedList {
StackNode root;
StackNode top;
StackAsLinkedList()
{
this.root = null;
this.top = null;
}
static class StackNode {
int data;
StackNode next;
StackNode(int data)
{
//Constructor here
this.data = data;
next = null;
}
}
public boolean isEmpty()
{
//Write your code here for the condition if stack is empty.
return root == null;
}
public void push(int data)
{
//Write code to push data to the stack.
StackNode newNode = new StackNode(data);
if(null == root)
{
root = newNode;
top = newNode;
}
else
{
top.next = newNode;
top = newNode;
}
}
public int pop()
{
//If Stack Empty Return 0 and print "Stack Underflow"
//Write code to pop the topmost element of stack.
//Also return the popped element
if(isEmpty())
{
System.out.println("Stack Underflow");
return 0;
}
int topElement = top.data;
StackNode curr = root;
while(curr.next != top)
{
curr = curr.next;
}
top = curr;
top.next = null;
return topElement;
}
public int peek()
{
//Write code to just return the topmost element without removing it.
if(isEmpty())
{
System.out.println("Stack is empty");
return -1;
}
return top.data;
}
//Driver code
public static void main(String[] args)
{
StackAsLinkedList sll = new StackAsLinkedList();
sll.push(10);
sll.push(20);
sll.push(30);
System.out.println(sll.pop() + " popped from stack");
System.out.println("Top element is " + sll.peek());
}
}