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MedianofTwoSortedArrays.py
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69 lines (54 loc) · 1.88 KB
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class Solution:
def findMedianSortedArrays(self, nums1: List[int], nums2: List[int]) -> float:
len1=len(nums1)
len2=len(nums2)
totalL = len1 + len2
# even = True
# if totalL%2!=0:
# even = False
medianL = int(totalL/2) +1
j=0
k=0
newList=[]
if len1>0 and len2>0:
for i in range(medianL):
if nums1[j]<nums2[k]:
newList.append(nums1[j])
if j< len1-1:
j += 1
else:
newList=newList+nums2[k:medianL+k-j]
break
elif nums1[j]>nums2[k]:
newList.append(nums2[k])
if k< len2-1:
k+=1
else:
newList=newList+nums1[j:medianL-k+j]
break
else:
newList.append(nums1[j])
newList.append(nums2[k])
i+=1
#end=False
if j< len1-1:
j += 1
else:
newList=newList+nums2[k:medianL+k-j]
break
if k<len2-1:
k+=1
else:
newList=newList+nums1[j:medianL-k+j]
break
#end=True
if len(newList)<medianL:
if len1==0 :
newList=newList+nums2[k:medianL+k-j]
elif len2==0:
newList=newList+nums1[j:medianL-k+j]
if totalL%2==0:
return (float(newList[medianL-2]+newList[medianL-1])/2)
else:
return (float(newList[medianL-1]))
############################################################################