-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy pathpacketQueueDelay.py
More file actions
190 lines (140 loc) · 5.64 KB
/
packetQueueDelay.py
File metadata and controls
190 lines (140 loc) · 5.64 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
'''
Jordan Paul
Homework problem P.6 part A, B, C, D
2 4 7 9 12
a -> 1 3 6 5 8 10 11 (arriving)
t -> 0 -- 1 -- 2 -- 3 -- 4 -- 5 -- 6 -- 7 -- 8 -- 9 -- ....
l -> 1 .... (leaving)
Assuming FIFO service, indicate the time at which packet 2 trhough 12 each leave the queue.
for each packet, what is the delay between its arrival and transmitted
'''
def fifo():
arrivals = [[1, 2], [3, 4], [6], [5, 7], [], [8, 9], [], [10], [11, 12]]
queue = []
leaving = {}
t = 0
while arrivals or queue:
if arrivals:
for item in arrivals.pop(0):
queue.append([item, t])
print(f"Package: {item} Arrived TIME: {t}")
if queue:
packet, arrive = queue.pop(0)
leaving[packet] = [arrive, t]
print(f"Packet {packet} leaving TIME: {t} queue: {len(queue)}")
t += 1
print("")
leaving = {packet: leaving[packet] for packet in range(1, len(leaving) + 1)}
avg_dly = 0
for packet, leave in leaving.items():
arrive, depart = leave
print(f"packet: {packet} arrival: {arrive} leaving: {depart} delay: {depart - arrive}")
avg_dly += depart - arrive
print("Average delay: ", round(avg_dly / len(leaving), 4))
'''
Now assume a priority service, and assume that odd-numbered packets are high prioroty, and
even-numbered packets are low priority
'''
def priority():
# t= 0 1 2 3 4 5 6 7 8
arrivals = [[1, 2], [3, 4], [6], [5, 7], [], [8, 9], [], [10], [11, 12]]
leaving = {}
even_queue = []
odds_queue = []
t = 0
while arrivals or (even_queue or odds_queue):
if arrivals:
for item in arrivals.pop(0):
if item % 2 == 0:
even_queue.append((item, t))
print(f"Package: {item} Arrived TIME: {t}")
else:
odds_queue.append((item, t))
print(f"Package: {item} Arrived TIME: {t}")
packet = None
if len(odds_queue) > 0:
packet = odds_queue.pop(0)
print(f"Packet {packet[0]} (ODD) leaving TIME: {t} even_queue: {len(even_queue)} odds_queue: {len(odds_queue)}")
elif len(even_queue) > 0:
packet = even_queue.pop(0)
print(f"Packet {packet[0]} (EVEN) leaving TIME: {t} even_queue: {len(even_queue)} odds_queue: {len(odds_queue)}")
if packet:
leaving[packet[0]] = [packet[1], t]
t += 1
print()
for i in range(1, len(leaving) + 1):
packet = leaving[i]
print(f"packet: {i} arrival: {packet[0]} leaving: {packet[1]} delay: {packet[1] - packet[0]}")
'''
Now assume round robin server. Assume that packets 1, 2, 3, 4, 6, 11, 12 are from class 1,
and packets 4, 5, 7, 8, 9, 10 are from class 2
'''
def round_robin():
# t= 0 1 2 3 4 5 6 7 8
arrivals = [[1, 2], [3, 4], [6], [5, 7], [], [8, 9], [], [10], [11, 12]]
class1 = [1, 2, 3, 6, 11, 12]
class2 = [4, 5, 7, 8, 9, 10]
class_n = []
for c1, c2 in zip(class1, class2):
class_n.extend([c1, c2])
queue = {}
leaving = []
t = 0
while arrivals or class_n:
if arrivals:
for item in arrivals.pop(0):
queue[item] = t
print(f"Package: {item} Arrived TIME: {t}")
if class_n and class_n[0] in queue:
c = class_n.pop(0)
packet = [c, queue.pop(c), t]
leaving.append(packet)
print(f"Packet {c} Leaving: TIME: {t} queue: {len(queue)}")
t += 1
ordered = {}
for packet_leaving in leaving:
packet, arrive, leave = packet_leaving
ordered[packet] = [arrive, leave]
print("\n")
for i in range(1, len(ordered) + 1):
arrive, leave = ordered[i]
print(f"packet: {i} arrival: {arrive} leaving: {leave} delay: {leave - arrive}")
'''
Now assume weighted fair queuing (WFQ) service. Assume that odd-numbered packets are from class 1,
and even0numbered packes are from class 2. Class 1 has weight of 2, while class 2 has WFG weight of 1
#NOTE think this isnt fully done correctly
'''
def weighted_fair():
# t= 0 1 2 3 4 5 6 7 8
arrivals = [[1, 2], [3, 4], [6], [5, 7], [], [8, 9], [], [10], [11, 12]]
class1 = [1, 3, 5, 7, 9, 11]
class2 = [2, 4, 6, 8, 10, 12]
weight1, weight2 = 2, 1
queue = {}
leaving = []
weight = {}
t = 0
while arrivals or (class1 or class2):
if arrivals:
for item in arrivals.pop(0):
queue[item] = t
print(f"Package: {item} Arrived TIME: {t}")
if class1 and class1[0] in queue and class1[0] // weight1 < class2[0] // weight2:
c = class1.pop(0)
packet = [c, queue.pop(c), t]
leaving.append(packet)
print(f"Packet {c} Leaving: TIME: {t} queue: {len(queue)}")
elif class2 and class2[0] in queue:
c = class2.pop(0)
packet = [c, queue.pop(c), t]
leaving.append(packet)
print(f"Packet {c} Leaving: TIME: {t} queue: {len(queue)}")
t += 1
ordered = {}
for packet_leaving in leaving:
packet, arrive, leave = packet_leaving
ordered[packet] = [arrive, leave]
print("\n")
for i in range(1, len(ordered) + 1):
arrive, leave = ordered[i]
print(f"packet: {i} arrival: {arrive} leaving: {leave} delay: {leave - arrive}")