leetcode/412.fizz-buzz.java at master · jnriver/leetcode · GitHub

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
/*
 * @lc app=leetcode.cn id=412 lang=java
 *
 * [412] Fizz Buzz
 *
 * https://leetcode-cn.com/problems/fizz-buzz/description/
 *
 * algorithms
 * Easy (67.40%)
 * Likes:    115
 * Dislikes: 0
 * Total Accepted:    79.2K
 * Total Submissions: 116.1K
 * Testcase Example:  '3'
 *
 * 写一个程序，输出从 1 到 n 数字的字符串表示。
 *
 * 1. 如果 n 是3的倍数，输出“Fizz”；
 *
 * 2. 如果 n 是5的倍数，输出“Buzz”；
 *
 * 3.如果 n 同时是3和5的倍数，输出 “FizzBuzz”。
 *
 * 示例：
 *
 * n = 15,
 *
 * 返回:
 * [
 * ⁠   "1",
 * ⁠   "2",
 * ⁠   "Fizz",
 * ⁠   "4",
 * ⁠   "Buzz",
 * ⁠   "Fizz",
 * ⁠   "7",
 * ⁠   "8",
 * ⁠   "Fizz",
 * ⁠   "Buzz",
 * ⁠   "11",
 * ⁠   "Fizz",
 * ⁠   "13",
 * ⁠   "14",
 * ⁠   "FizzBuzz"
 * ]
 *
 *
 */

import java.util.List;
import java.util.stream.Collectors;

// @lc code=start
class Solution {
    public List<String> fizzBuzz(int n) {
        List<String> answer = new ArrayList<String>();
        for (int i = 1; i <= n; i++) {
            StringBuffer sb = new StringBuffer();
            if (i % 3 == 0) {
                sb.append("Fizz");
            }
            if (i % 5 == 0) {
                sb.append("Buzz");
            }
            if (sb.length() == 0) {
                sb.append(i);
            }
            answer.add(sb.toString());
        }
        return answer;
    }
}
// @lc code=end