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Copy pathlswrc.cpp
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76 lines (71 loc) · 1.61 KB
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#include <bits/stdc++.h>
#include <string>
#include <unordered_set>
#include <utility>
using namespace std;
typedef long long ll;
typedef pair<ll, ll> pll;
typedef vector<bool> vbl;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<string> vstr;
typedef vector<pll> vpll;
#define endl '\n'
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
constexpr ll mod = 1000000007;
inline void Parvez() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
template <class T> inline istream &operator>>(istream &in, vector<T> &v) {
for (T &x : v) {
in >> x;
}
return in;
}
template <class T> inline ostream &operator<<(ostream &out, vector<T> &v) {
if (v.empty())
return out;
for (ll i = 0; i < v.size() - 1; i++) {
out << v[i] << ' ';
}
out << v[v.size() - 1];
return out;
}
string lswrc(string s) {
unordered_set<char> st;
ll l = 0, r = 0;
pair<ll, ll> ans;
while (r < s.size() and l < s.size()) {
if (st.find(s[r]) == st.end()) {
st.insert(s[r]);
r++;
if (r - l > ans.second - ans.first) {
ans = {l, r};
}
} else {
while (s[l] != s[r]) {
st.erase(s[l]);
l++;
}
st.erase(s[r]);
l++;
}
}
return s.substr(ans.first, ans.second - ans.first);
}
void solution(ll &T) {
string s;
cin >> s;
cout << lswrc(s) << endl;
}
signed main() {
Parvez();
ll TT = 1;
// cin>>TT;
for (ll T = 1; T <= TT; T++)
solution(T);
return 0;
}