From 6148f24f6e4ccda52b74179ebad7dce205b96fde Mon Sep 17 00:00:00 2001
From: HpEser <turanknt05@gmail.com>
Date: Fri, 27 May 2022 12:36:32 +0200
Subject: [PATCH] PyCoders Week2 Homework

---
 assignment_1.py | 26 ++++++++++++++++++++++++++
 assignment_2.py | 10 ++++++++++
 assignment_3.py | 16 ++++++++++++++++
 3 files changed, 52 insertions(+)
 create mode 100644 assignment_1.py
 create mode 100644 assignment_2.py
 create mode 100644 assignment_3.py

diff --git a/assignment_1.py b/assignment_1.py
new file mode 100644
index 0000000..d0951f6
--- /dev/null
+++ b/assignment_1.py
@@ -0,0 +1,26 @@
+# HOMEWORK_1
+# Write a Python program which executes following rules on this given list => numbers = [2, 3, 5, 7, 11, 13, 17, 19]
+# -take an input(number) from the user
+# -take out the first element of the list and put it at the end. Do this x times that in the first step the user indicated.
+# -print the list
+# -(OPTIONAL) make sure there is not an error while taking input
+
+numbers = []
+for i in range(2,20):
+    check = True
+    for j in range(2,i):
+        if(i%j == 0):
+            check = False
+            break
+    if(check):
+        numbers.append(i)
+
+print(numbers)
+
+
+n = int(input("Enter n: "))
+
+for i in range(n):
+    numbers.append(numbers.pop(0))
+
+print(numbers)
\ No newline at end of file
diff --git a/assignment_2.py b/assignment_2.py
new file mode 100644
index 0000000..8474a53
--- /dev/null
+++ b/assignment_2.py
@@ -0,0 +1,10 @@
+# Write a Python program that returns the following dictionary with sorted values.
+# NOTE: Dictonaries have keys and values. Here the values are lists.
+# So, the returned dictonary should have sorted values(list).
+
+data = { 'a': [5, 3, 9, 0, 2, 3, 1], 'b': [4, 7, 5, 1, 2], 'c': [8, 1, 3, 2, 4] }
+
+for i in data:
+    data[i] = sorted(data[i])
+
+print(data)
\ No newline at end of file
diff --git a/assignment_3.py b/assignment_3.py
new file mode 100644
index 0000000..8e75fb1
--- /dev/null
+++ b/assignment_3.py
@@ -0,0 +1,16 @@
+# Write a Python program that returns a dictionary 
+# which consists the unique elements in the following tuple as keys and 
+# the number of occurrences of elements as values.
+
+
+tuple1 = (20, 10, 60, 70, 50, 20, 80, 20, 10, 20, 60, 60, 50)
+
+new = {}
+s = set(tuple1) 
+
+for i in s:
+    new[i]=tuple1.count(i)
+
+print(new)
+
+