From c94c4c82c430ce8838b7358b6db3e296025b1720 Mon Sep 17 00:00:00 2001
From: "codeflash-ai[bot]"
 <148906541+codeflash-ai[bot]@users.noreply.github.com>
Date: Tue, 17 Mar 2026 07:44:18 +0000
Subject: [PATCH] Optimize find_leaf_nodes
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The optimized function cuts runtime from 59.4 ms to 0.157 ms (~378× faster) by building a set of edge["source"] values and using a single list comprehension to filter nodes instead of the original nested node×edge loop. The key insight is that membership checks against a precomputed set are O(1), turning the algorithm from O(n·m) into O(n+m); the line profiler shows the inner edge loop accounted for ~99% of the original time, so eliminating it yields the large win. It also short-circuits the no-edges case by returning a shallow copy for minimal overhead and wraps set construction in a try/except to fall back to the original nested loop if sources are unhashable or the 'source' key is missing, preserving the original exception behavior. Trade-offs: set construction adds a small upfront cost and a couple of microbenchmarks (empty-nodes and the missing-key fallback) show marginal regressions, but these are rare compared with the huge speedup on typical graphs.
---
 src/algorithms/graph.py | 32 +++++++++++++++++++++++---------
 1 file changed, 23 insertions(+), 9 deletions(-)

diff --git a/src/algorithms/graph.py b/src/algorithms/graph.py
index 777ea3b..9bef300 100644
--- a/src/algorithms/graph.py
+++ b/src/algorithms/graph.py
@@ -52,15 +52,29 @@ def find_last_node(nodes, edges):
 
 def find_leaf_nodes(nodes: list[dict], edges: list[dict]) -> list[dict]:
     """Find all leaf nodes (nodes with no outgoing edges)."""
-    leaf_nodes = []
-    for node in nodes:
-        is_leaf = True
-        for edge in edges:
-            if edge["source"] == node["id"]:
-                is_leaf = False
-                break
-        if is_leaf:
-            leaf_nodes.append(node)
+    # If there are no edges, every node is a leaf; avoid accessing node["id"]
+    if not edges:
+        return nodes[:]
+
+    # Attempt to build a set of sources for O(1) membership checks.
+    # If building the set fails (e.g., unhashable source, missing "source" key),
+    # fall back to the original nested-loop logic to preserve behavior and exceptions.
+    try:
+        sources = {edge["source"] for edge in edges}
+    except Exception:
+        leaf_nodes = []
+        for node in nodes:
+            is_leaf = True
+            for edge in edges:
+                if edge["source"] == node["id"]:
+                    is_leaf = False
+                    break
+            if is_leaf:
+                leaf_nodes.append(node)
+        return leaf_nodes
+
+    # Fast path using the precomputed set of sources.
+    leaf_nodes = [node for node in nodes if node["id"] not in sources]
     return leaf_nodes