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BinaryTreeLevelOrderTraversalII.java
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77 lines (67 loc) · 1.9 KB
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package leetcode;
import java.util.ArrayList;
import java.util.LinkedList;
import java.util.List;
import java.util.Queue;
/**
* Project Name : Leetcode
* Package Name : leetcode
* File Name : BinaryTreeLevelOrderTreaversalII
* Creator : Edward
* Date : Sep, 2017
* Description : 107. Binary Tree Level Order Traversal II (102 follow up)
*/
public class BinaryTreeLevelOrderTraversalII {
/**
*
For example:
Given binary tree [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
[
[15,7],
[9,20],
[3]
]
time : O(n)
space : O(n)
* @param root
* @return
*/
public static List<List<Integer>> levelOrderBottom(TreeNode root) {
List<List<Integer>> res = new ArrayList<>();
if (root == null) return res;
Queue<TreeNode> queue = new LinkedList<>();
queue.offer(root);
while (!queue.isEmpty()) {
int size = queue.size();
List<Integer> list = new ArrayList<>();
for (int i = 0; i < size; i++) {
TreeNode cur = queue.poll();
if (cur.left != null) queue.offer(cur.left);
if (cur.right != null) queue.offer(cur.right);
list.add(cur.val);
}
res.add(0, list);
}
return res;
}
public static List<List<Integer>> levelOrderBottom2(TreeNode root) {
List<List<Integer>> res = new ArrayList<>();
if (root == null) return res;
helper(res, root, 0);
return res;
}
public static void helper(List<List<Integer>> res, TreeNode root, int level) {
if (root == null) return;
if (level >= res.size()) {
res.add(0, new ArrayList<>());
}
res.get(res.size() - level - 1).add(root.val);
helper(res, root.left, level + 1);
helper(res, root.right, level + 1);
}
}