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arrayToBinaryTree.js
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85 lines (82 loc) · 2.11 KB
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// 参考leetcode的二叉树序列化
// 特别注意这棵树不一定是完全二叉树
// convert [1,2,3,null,null,4,5]
// to
// {
// val: 1,
// left: {
// val: 2,
// left: null,
// right: null,
// },
// right: {
// val: 3,
// left: {
// val: 4,
// left: null,
// right: null,
// },
// right: {
// val: 5,
// left: null,
// right: null,
// }
// }
// }
/**
* 迭代实现
* @param {number[]} arr
* @return {object}
*/
function arrayToBinaryTree(arr) {
if(arr[0] === null) return {val: null, left: null, right: null};
let queue = [];
let root = {
val: arr[0],
left: null,
right: null
}
arr.shift();
queue.push(root);
while(queue.length !== 0){
// 下一层的节点数量
let nextLevelCount = queue.length * 2;
let node;
for(let i=0; i<nextLevelCount; i++){
let val = arr.shift();
// 这里不加这个会导致死循环,因为最后一层的节点会一直保存在queue里面
if(val === undefined){
return root;
}
if(i % 2 === 0) {
// left child
node = queue.shift();
if(val === null) {
node.left = null;
} else {
node.left = {
val,
left: null,
right: null,
};
queue.push(node.left);
}
} else {
// right child
if(val === null){
node.right = null;
} else {
node.right = {
val,
left: null,
right: null,
}
queue.push(node.right);
}
}
}
}
return root;
}
let case1 = [1,2,3,null,null,4,5, 6, null, 7, 8,null];
console.log(arrayToBinaryTree(case1));