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// Source : https://leetcode.com/problems/jump-game/
// Author : cornprincess
// Date : 2020-04-17
/*****************************************************************************************************
*
* Given an array of non-negative integers, you are initially positioned at the first index of the
* array.
*
* Each element in the array represents your maximum jump length at that position.
*
* Determine if you are able to reach the last index.
*
* Example 1:
*
* Input: [2,3,1,1,4]
* Output: true
* Explanation: Jump 1 step from index 0 to 1, then 3 steps to the last index.
*
* Example 2:
*
* Input: [3,2,1,0,4]
* Output: false
* Explanation: You will always arrive at index 3 no matter what. Its maximum
* jump length is 0, which makes it impossible to reach the last index.
*
******************************************************************************************************/
package JumpGame;
public class JumpGame {
// Greedy algorithms
// Time complexity: o(n)
// Space complexity o(1)
public boolean canJump(int[] nums) {
if (nums == null || nums.length == 0) {
return false;
}
int n = nums.length;
int canMoveMaxLength = 0;
for (int i = 0; i < n; i++) {
if (i <= canMoveMaxLength) {
canMoveMaxLength = Math.max(canMoveMaxLength, i + nums[i]);
if (canMoveMaxLength >= n - 1) {
return true;
}
}
}
return false;
}
}