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// Source : https://leetcode.com/problems/happy-number/solution/kuai-le-shu-by-leetcode/
// Author : cornprincess
// Date : 2020-04-21
/*****************************************************************************************************
*
* Write an algorithm to determine if a number n is "happy".
*
* A happy number is a number defined by the following process: Starting with any positive integer,
* replace the number by the sum of the squares of its digits, and repeat the process until the number
* equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those
* numbers for which this process ends in 1 are happy numbers.
*
* Return True if n is a happy number, and False if not.
*
* Example:
*
* Input: 19
* Output: true
* Explanation:
* 12 + 92 = 82
* 82 + 22 = 68
* 62 + 82 = 100
* 12 + 02 + 02 = 1
******************************************************************************************************/
package HappyNumber;
import java.util.HashSet;
import java.util.Set;
public class HappyNumber {
// Time complexity O(logn)
// Space complexity O(logn)
public boolean hashSet(int n) {
Set<Integer> set = new HashSet<>();
while (n != 1 && !set.contains(n)) {
set.add(n);
n = getNext(n);
}
return n == 1;
}
// Time complexity O(logn)
// Space complexity O(1)
public boolean circle(int n) {
int slow = n;
int fast = getNext(n);
while (fast != 1 && fast != slow) {
slow = getNext(slow);
fast = getNext(getNext(fast));
}
return fast == 1;
}
private int getNext(int n) {
int result = 0;
while (n > 0) {
int digit = n % 10;
n /= 10;
result += digit * digit;
}
return result;
}
}